TRẦN NGỌC KHÁNH NHƯ

Phân tích đa thức sau thành nhân tử: (Test)

<p><b> DẠNG TOÁN PHÂN TÍCH ĐA THỨC THÀNH NHÂN TỬ</b></p><p></p><div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi-j1BXv25_EwIQRI7ndmJFIY5NSNpQcq-rQJfrz7xQe-VOaZzC2dD0SH41xTyPTSNIvaU_KbQlQasaZCUsu3YQ6Xxo5bbNh6ddJPystA5cM4EU4UdfQPY9e6M63cud-OPk6XFfaupzCuoSnNaqGfpiOMNcgRrXtfEVvARl8rX7-lVWpehh5DIuhu1eARw/s270/A1.jpg" imageanchor="1" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em;"><img border="0" data-original-height="270" data-original-width="90" height="365" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi-j1BXv25_EwIQRI7ndmJFIY5NSNpQcq-rQJfrz7xQe-VOaZzC2dD0SH41xTyPTSNIvaU_KbQlQasaZCUsu3YQ6Xxo5bbNh6ddJPystA5cM4EU4UdfQPY9e6M63cud-OPk6XFfaupzCuoSnNaqGfpiOMNcgRrXtfEVvARl8rX7-lVWpehh5DIuhu1eARw/w121-h365/A1.jpg" width="121" /></a></div><br /><b><br /></b><p></p>
<div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg7oxhO6xPu9rEnFZxEvth7T_L07Nwp5V0m6xeJa_n34SrLENOZQ03cn_RNibzFu5XnqbLPVr2GaxwW6WA4ob-nJ6yQhDv6CIWKsRLR6SXUrSItoH8EoMBB8CELJ9BnbfBP0hOlvNmNn9nuIIkI2quiohDLCKkHQyATlSGHHEJXY8dxH61al11ogO963Ps/s203/A2.jpg" imageanchor="1" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em;"><img border="0" data-original-height="203" data-original-width="160" height="243" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg7oxhO6xPu9rEnFZxEvth7T_L07Nwp5V0m6xeJa_n34SrLENOZQ03cn_RNibzFu5XnqbLPVr2GaxwW6WA4ob-nJ6yQhDv6CIWKsRLR6SXUrSItoH8EoMBB8CELJ9BnbfBP0hOlvNmNn9nuIIkI2quiohDLCKkHQyATlSGHHEJXY8dxH61al11ogO963Ps/w191-h243/A2.jpg" width="191" /></a></div><br /><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><span style="font-size: medium;"><b>1A = $- 6x + 9 - y^2 + x^2$ </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">1. Rewrite it in the form $a^2−2ab+b^2$, where a=3 and b=x.<br />
      $3^2−2(3)(x)+x^2−y^2$<br />
2. Use Square of Difference:$(a−b)^2=a^2−2ab+b^2$.<br />
      $(3−x)^2−y^2$<br />
3. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
      $(3−x+y)(3−x−y)$</span>
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<div><br /></div><span style="font-size: medium;"><b>1B = $9x^2 — 16y^2$ </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Find the Greatest Common Factor (GCF).<br />
  GCF = 33<br />

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)<br />
  $3(\Large{\frac{9x^2}{3}+\frac{−6y^2}{3}})$<br />

3. Simplify each term in parentheses.<br />
  $3(3x^2−2y^2)$<br />
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<span style="font-size: medium;"><b>2A = $x^2 + 4x + 4 - y^2$ </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2+2ab+b^2$, where a=x and b=2.<br />
      $x^2+2(x)(2)+2^2−y^2$<br />
2. Use Square of Sum: $(a+b)^2=a^2+2ab+b^2$.<br />
      $(x+2)^2−y^2$<br />
3. Use Difference of Squares: $a2−b2=(a+b)(a−b)$.<br />
      $(x+2+y)(x+2−y)$</span>
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  <div><br /></div><span style="font-size: medium;"><b> 2B = $25x^2 — 4y^2$ </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2−b^2$, where a=5x and b=2y.<br />
  $(5x)^2−(2y)^2$<br />

2. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $(5x+2y)(5x−2y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 3A = $x^2 — 5xy - 4x + 20y$ </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Factor out common terms in the first two terms, then in the last two terms.<br />
  x(x−5y)−4(x−5y)<br />

2. Factor out the common term x−5y.<br />
  (x−5y)(x−4)
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<div><br /></div><span style="font-size: medium;"><b> 3B = $4x^2 — 4x + 1 — y^2$</b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<span style="font-size: medium;"> L = $4x^2 — 4x + 1 — y%2$<br />
= $(4x^2 — 4x + 1) — y^2$<br />
= $(2x)^2 -2.2x.1 +1^2 - y^2$	  (có dạng $a^2 -2ab + b^2 = (a – b)^2$<br />
= $[(2x)^2 -2.2x.1 +1^2] - y^2$<br />
= $(2x – 1)^2 – y^2$ 		    (có dạng $a^2 – b^2 = (a + b)(a - b)$<br />
= $[(2x -1)+(y)] [(2x -1)-(y)]$<br />
= $(2x -1 + y)(2x -1 –y)$
</span>
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<span style="font-size: medium;"><b> 4A = $x^2 - 2xy + y^2 – 49$ </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<span style="font-size: medium;">1. Rewrite it in the form $a^2−2ab+b^2$, where a = x and b = y.<br />
  $x^2−2(x)(y)+y^2−49$<br />

2. Use Square of Difference: $(a−b)^2=a^2−2ab+b^2$.<br />
  $(x−y)^2−49$<br />

3. Rewrite it in the form $a^2−b^2$, where a=x−y and b=7.<br />
  $(x−y)^2−7^2$<br />

4. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $(x−y+7)(x−y−7)$
 </span>
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<div><br /></div><span style="font-size: medium;"><b> 4B = $16x^2 - 4y^2$ </b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Find the Greatest Common Factor (GCF).<br />
  GCF = 4<br />

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)<br />
  $4\Large{(\frac{16x^2}{4}+\frac{−4y^2}{4})}$<br />

3. Simplify each term in parentheses.<br />
  $4(4x^2−y^2)$<br />

4.Rewrite $4x^2−y^2$ in the form $a^2−b^2$, where a = 2x and b = y.<br />
  $4((2x)^2−y^2)$<br />

5. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $4(2x+y)(2x−y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 5A = $x^2 — 12x + 36 — 81y^2$ </b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2−2ab+b^2$, where a=x and b=6.<br />
  $2x^2−2(x)(6)+6^2−81y^2$<br />

2. Use Square of Difference: $2(a−b)^2=a^2−2ab+b^2$.<br />
  $(x−6)^2−81y^2$<br />

3. Rewrite it in the form $a^2−b^2$, where a=x−6 and b=9y.<br />
  $(x−6)^2−(9y)^2$<br />

4. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $(x−6+9y)(x−6−9y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 5B = $9x^2 — y^2$ </b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">1. Rewrite it in the form $a^2−b^2$, where a=3x and b=y.<br />
  $(3x)^2−y^2$<br />

2. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $(3x+y)(3x−y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 6A = $x^2 — 10xy + 25y^2 – 16$</b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2−2ab+b^2$, where a=x and b=5y.<br />
  $x^2−2(x)(5y)+(5y)^2−16$<br />

2. Use Square of Difference: $(a−b)^2 = a^2 − 2ab + b^2$.<br />
  $(x−5y)^2−16$<br />

3. Rewrite it in the form $a^2 − b^2$, where a = x − 5y and b = 4 .<br />
  $(x − 5y)^2 − 4^2$<br />

4. Use Difference of Squares:$ a^2 − b^2=(a + b)(a − b)$.<br />
  $(x − 5y + 4)(x − 5y − 4)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 6B = $4x^2 - 36y^2$ </b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Find the Greatest Common Factor (GCF).<br />
GCF = 4<br />

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)<br />
  $4\Large{(\frac{4x^2}{4}+\frac{−36y^2}{4})}$<br />

3. Simplify each term in parentheses.<br />
  $4(x^2−9y^2)$<br />

4.Rewrite $x2−9y2$ in the form $a2−b2$, where a=x and b=3y.<br />
  $4(x^2−(3y)^2)$<br />

5. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $4(x+3y)(x−3y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 7A = $x^2 — 2x + 1 — y^2$ </b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a2−2ab+b2$, where a=x and b=1.<br />
  $x^2−2(x)(1)+1^2−y^2$<br />

2. Use Square of Difference: $(a−b)^2=a^2−2ab+b^2$.<br />
  $(x−1)^2−y^2$<br />

3. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $(x−1+y)(x−1−y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 8A = $49x^2 — 9y^2$</b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2−b%2$, where a=7x and b=3y.<br />
  $(7x)^2−(3y)^2$<br />

2. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$.<br />
  $(7x+3y)(7x−3y)$
</span>
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<div><br /></div><span style="font-size: medium;"><b> 8A = $3x(5x + y) + 25x^2 — y^2$ </b>
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<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 
  $3x(5x + y) + (5x)^2 — y^2$<br />
  $3x(5x + y) + (5x - y)(5x +y)$<br />
  $(5x + y) [3x +(5x - y)]$<br />
  $(5x + y) (3x +5x - y)$ <br />
    $(5x + y) (8x - y)$

</span>
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  <div><br /></div><span style="font-size: medium;"><b> 8B = $121x^2— 64y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">1. Rewrite it in the form $a^2 − b^2$, where a = 11x and b = 8y.<br />
  $(11x)^2−(8y)^2$<br />

2. Use Difference of Squares: $a^2 − b^2=(a + b)(a − b)$.<br />
  $(11x + 8y)(11x − 8y)$
</span>
</div>
</div></div>

<div><br /></div><span style="font-size: medium;"><b> 9A = $x^2 - 8x + 16 – y2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2 − 2ab + b^2$, where a = x and b = 4.<br />
    $x^2 − 2(x)(4) + 4^2 − y^2$<br />

2. Use Square of Difference: $(a − b)^2 = a^2 − 2ab + b^2$.<br />
  $(x−4)^2 − y^2$<br />

3. Use Difference of Squares: $a^2 − b^2 = (a + b)(a − b)$.<br />
  $(x – 4 + y)(x – 4 − y)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b>11A = $x^2— 2x — y^2 + 1$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> = $x^2 - 2x + 1 - y^2$<br />
  = $(x^2 - 2x + 1) - y^2$<br />
  = $(x – 1)^2 - y^2$<br />
  = $(x – 1 + y)(x – 1 - y)$

</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 11B = $16x^2 — 144y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Find the Greatest Common Factor (GCF).<br />
  GCF = 16<br />

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)<br />
  $16(x^2) – 16(9y^2)$<br />

3. Simplify each term in parentheses.<br />
  $16(x^2 − 9y^2)$<br />

4.Rewrite $x2 − 9y2$ in the form $a^2 – b^2$, where a = x and b = 3y.<br />
  $16(x^2 − (3y)^2)$<br />

5. Use Difference of Squares: $a^2 – b^2 = (a + b)(a − b)$.<br />
  $16(x + 3y)(x − 3y)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 12A = $x^2 — 6x + 9 — y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2−2ab+b^2$, where a = x and b = 3.<br />
  $x^2 − 2(x)(3) + 3^2 − y^2$<br />

2. Use Square of Difference: $(a − b)^2 = a^2 − 2ab + b^2$.<br />
  $(x−3)^2 − y^2$<br />

3. Use Difference of Squares: $a^2 − b^2 = (a + b)(a − b)$.<br />
  $(x – 3 + y)(x – 3 − y)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 12B = $81x^2 — 169ỵ^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2 − b^2$, where a = 9x and b = 13y.<br />
  $(9x)^2 − (13y)^2$<br />

2. Use Difference of Squares: $a^2 − b^2=(a + b)(a − b)$.<br />
  $(9x + 13y)(9x − 13y)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 12C = $xy — 3x + y^2 - 3y$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">   = $(xy + y^2) — (3x + 3y)$ <br />
  = $y(x + y) — 3(x +y)$<br />
  = $(x + y) (y— 3)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 13A = $x^2 + 10x + 25 — 64y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">   = $x^2 + 10x + 5^2 — 64y^2$<br />
  = $(x^2 + 10x + 5^2) — 8^2y^2$<br />
  = $(x + 5)^2 — (8y)^2$<br />
  = $[(x + 5) + 8y] [(x + 5) - 8y] $<br />
  = $(x + 5 + 8y) (x + 5 - 8y) $
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 13B = $x^2 — 16y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2 − b^2$, where a = x and b = 4y.<br />
  $x^2 − (4y)^2$<br />

2. Use Difference of Squares: $a^2 − b^2 = (a + b)(a − b)$.<br />
  $(x + 4y)(x − 4y)$
</span>
</div>
</div></div>

<div><br /></div><span style="font-size: medium;"><b> C = $x^5 + x - 2x^4 – 2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Factor out common terms in the first two terms, then in the last two terms.<br />
      $x(x^4+1)−2(x^4+1)$<br />
2. Factor out the common term $x^4+1$.<br />
      $(x^4+1)(x−2)$</span>
</div>
</div></div>
  <div><br /></div><span style="font-size: medium;"><b> 14A = $5x(x — y) + 9x — 9y$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">   $5x(x — y) + 9(x — y)$<br />
    = $(x — y)(5x + 9)$
  </span>
</div>
</div></div>

<div><br /></div>
<span style="font-size: medium;"><b> 14B = $196x^2 — 9y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">   = $(14x)^2 — (3y)^2$<br />
    = $(14x)^2 — (3y)^2$<br />
    = $(14x+3y)(14x−3y)$

</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> 15A = $x^2 — 4xy + 4y^2 — 36$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Rewrite it in the form $a^2 − 2ab + b^2$, where a = x and b = 2y.<br />
  $x^2 − 2(x)(2y) + (2y)^2 − 36$<br />

2. Use Square of Difference:   $(a − b)^2 = a^2 − 2ab + b^2$.<br />
  $(x − 2y)^2 − 36$<br />

3. Rewrite it in the form $a^2 − b^2$, where a = x − 2y and b = 6.<br />
  $(x − 2y)^2 − 6^2$<br />

4. Use Difference of Squares:$a^2 − b^2 = (a + b)(a − b)$.<br />
  $(x − 2y + 6)(x − 2y − 6)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b>15B = $225x^2 — 9y^2$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 1. Find the Greatest Common Factor (GCF).<br />
  GCF = 9<br />

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)<br />
   $9.25x^2 − 9.y^2)$<br />
  $9\Large{(\frac{225x^2}{9} + \frac{−9y^2}{9})}$<br />

3. Simplify each term in parentheses.<br />
  $9(25x^2 − y^2)$<br />

4. Rewrite $25x^2 − y^2$ in the form $a2 − b2$, where a = 5x and b = y.<br />
  $9((5x)^2 − y^2)$<br />

5. Use Difference of Squares:$a^2 – b^2$ = (a + b)(a − b).<br />
  $9(5x + y)(5x − y)$
</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> Bài 5a </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> Bài 55</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> Bài 6a </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> Bài 66</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> Bài 7a </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> Bài 77</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> Bài 8a </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> Bài 88</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> Bài 9a </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> Bài 99</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> Bài 10a </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> Bài 10</span>
</div>
</div></div>

<div><br /></div><span style="font-size: medium;"><b>D = $ x^2 – 3$ </b>
<div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
</div>
<div>
<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">    $a = x; b = \sqrt{3}$<br />
  -> $E = x^2 – (\sqrt{3})^2$<br />
E có dạng $a^2 – b^2 = (a +b)(a –b)$E = $(x + \sqrt{3})(x - \sqrt{3})$</span>
</div>
</div></div>
<div><br /></div><span style="font-size: medium;"><b> E = $ x^3 – 2$ </b>
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<span style="font-size: medium;">   2 = $(\sqrt[3]{2})^3$<br />
E =$ x^3 - (\sqrt[3]{2})^3$<br />
      a = x; b = $\sqrt[3]{2}$<br />
      $a^3 – b^3 = (a – b)(a^2 + ab+ b^2)$<br />
E =$(x - \sqrt[3]{2})(x^2 + \sqrt[3]{2} x+ (\sqrt[3]{2})2)$<br />
      $(\sqrt[3]{2})^2 = 2^\frac{2}{3} =\sqrt[3]{2^2} $<br />
E = $(x - \sqrt[3]{2}) (x^2 +\sqrt[3]{2} + \sqrt[3]{2^2} )$</span>
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<div><br /></div><span style="font-size: medium;"><b> F = $x^5 – 3x^3 – 2x^2 + 6$ </b>
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<span style="font-size: medium;"> 1. Factor out common terms in the first two terms, then in the last two terms.<br />
      $x^3(x^2−3)−2(x^2−3)$<br />
2. Factor out the common term $x^2−3$<br />
      $(x^2−3)(x^3−2)$</span>
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<div><br /></div><span style="font-size: medium;"><b> G = $x^2 - 2x + 1 - y^2$</b>
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<span style="font-size: medium;"> 1. Rewrite it in the form $a^2−2ab+b^2$, where a=x and b=1.<br />
      $2x^2−2(x)(1)+1^2−y^2$<br />
2. Use Square of Difference: $(a−b)^2=a^2−2ab+b^2$.<br />
      $(x−1)^2−y^2$<br />
3. Use Difference of Squares: $a^2−b^2=(a+b)(a−b)$. <br />
       $(x−1+y)(x−1−y)$</span>
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Phân tích đa thức sau thành nhân tử: (Test)

DẠNG TOÁN PHÂN TÍCH ĐA THỨC THÀNH NHÂN TỬ 1A = $- 6x + 9 - y^2 + x^2$ 1. Rewrite it in the form $a^2−2ab+b^2$, where a=3 and b=x. ...

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href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjkxCEYHXEnR_VIosI48kTBm8tg7m0-fSVg8napoEEzNQVkJK5wqEnVPynWdwKAu9EMyRHkPZfv3S29FoxIeQscZTZGAn3OgLmsKB1EE-76Vdxehn98RK4IT_88mDPK7i9VmfbKTchOJGQAIhcoUbAV0iF2Vgv3tbeLQruQkq-lwIIi53uk1W9Gk4g_awo/s334/s5.jpg" imageanchor="1" style="clear: left; float: left; margin-bottom: 1em; margin-right: 1em;"><img border="0" data-original-height="324" data-original-width="334" height="457" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjkxCEYHXEnR_VIosI48kTBm8tg7m0-fSVg8napoEEzNQVkJK5wqEnVPynWdwKAu9EMyRHkPZfv3S29FoxIeQscZTZGAn3OgLmsKB1EE-76Vdxehn98RK4IT_88mDPK7i9VmfbKTchOJGQAIhcoUbAV0iF2Vgv3tbeLQruQkq-lwIIi53uk1W9Gk4g_awo/w471-h457/s5.jpg" width="471" /></a></div><br /><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div><br /></div><div>1) $\Large{\frac{4xy(2x^2 - xy) + (8x^3y3 - 6x^4y^2 + 2xy)}{(2xy)}}$<br /><span>    </span>$\Large{\frac{4xy(2x^2-xy)+(8x^3y^3 - 6x^4y^2 + 2xy)}{2xy}}$<br /><span>    </span>= $\Large{\frac{2xy(2.2x^2-2.xy) + 2xy(4x^2y^2 - 3x^2y^1 + 1xy)}{2xy}}$<br />Triệt tiêu thừa số chung: 2xy; rút gọn $2.2x^2-2.xy$ và bỏ ngoặc, ta có:<br /><span>    </span>A = (4x2−2xy) + (4x2y2−3x3y+1)<br />    <span>    </span>A = 4x2 − 2xy + 4x2y2 − 3x3y + 1<br /><br /> 2) $\Large{\frac{7x+6}{5x-1}+\frac{8x-9}{5x-1}}$     = $\Large{\frac{7x+6+8x-9)}{5x-1}}$<br />    <span>    </span>= $\Large{\frac{15x-3}{5x-1}}$<br />    <span>    </span>= $\Large{\frac{3(5x-1)}{5x-1}}$<br />Triệt tiêu 5x - 1<br />    <span>    </span>= 3  <br /><br />3) (x - 5)2 + (x + 3)(2 - x)A = $(x - 5)^2 + (x + 3)(2 - x)$<br />Mở rộng:<br />    <span>    </span>$(x−5)^2 = x^2 − 10x + 25$<br />    <span>    </span>$(x+3)(2−x): −x^2 − x + 6$<br /><span><br /></span><div><span>    </span>A = $x^2 − 10x + 25 − x^2 − x + 6$<br /><span>    </span>A = $x^2−x^2−10x−x+25+6$<br /><span>    </span>A = $11x + 31$<br /><br /><div> 4) $\Large{\frac{4}{x+2} - \frac{2}{x-2}+\frac{12x}{x^2 - 4}}$<br />    <span>    </span>A = $\frac{4}{x+2}$-$\frac{2}{x-2}$+$\frac{12x}{x^2 - 4}$<br />Bội Số Chung Nhỏ Nhất của $x + 2, x − 2, x^2 − 4$ </div><div><span>    </span>là $x^2 - 2^2$ = $(x + 2)(x − 2)$ </div><div> <span>   </span>A = $\Large{\frac{4 (x - 2) - 2 (x +2) + 12x}{x^2 - 4}}$<br />    <span>    </span>A = $\Large{\frac{4x - 8 - 2x - 4 + 12x}{x^2-4}}$<br />    <span>    </span>A = $\Large{\frac{- 12 + 14x}{x^2-4}}$A = $\Large{\frac{14x - 12}{x^2-4}}$<br /><br />5) $\Large{\frac{2xy(3x^2 - xy) + (6x^3y^3 - 12x^4y^2 + 3xy)}{ (3xy)}}$ </div><div> <span>    </span>A = $\Large{\frac{2xy(3x^2 - xy) + (6x^3y^3 - 12x^4y^2 + 3xy)}{3xy}}$<br />Áp dụng quy tắc: a+(b+c) = a+b+c <br />        <span>    </span>$2xy(3x^2−xy)+(6x^2y^2.3−12x^4y^2+3xy)$<br />    <span>    </span>A = $\Large{\frac{2xy(3x^2 − xy) + 6x^2y^2 − 12x^4y^2 + 3xy} {3xy}}$<br />Đặt xy làm thừa số chung, ta có:<br />    <span>    </span>A = $\Large{\frac{xy(6x^2 - 2xy + 6xy -12x^3y + 3)} {3xy}}$<br />    <span>    </span>A = $\Large{\frac{xy(6x^2 + 4xy - 12x^3y + 3)} {3xy}}$<br />Triệt tiêu x<br />    <span>    </span>A = $\Large{\frac{xy(6x^2 + 4xy - 12x^3y + 3)} {3xy}}$<br /><br />6)  $\Large{\frac{a-1}{a-2}+\frac{a-3}{a-2}}$<br /><span>    </span>= $\Large{\frac{(a -1)+(a -3)}{a-2}}$<br /><span>    </span>= $\Large{\frac{a -1+ a -3}{a -2}}$<br /><span>    </span>= $\Large{\frac{2a - 4}{a -2}}$<br /><span>    </span>= $\Large{\frac{2(a - 2)}{a -2}}$<br />`<span>    </span>= $2$<div><br />7) $(2x - 3)^2 + (x + 2)(1 - 4x)$    = 4x2 -12x + 9 + x - 4x2 +2 - 8x<br /><span>    </span>= 4x2 - 4x2 -12x + x  - 8x + 9 + 2     = - 19x +11<br /><br />8) $\Large{\frac{6x}{x^2-9}+\frac{5x}{x-3}+\frac{x}{x+3}}$     <br /><span>    </span>A= $\Large{\frac{6x}{x^2-9}+\frac{5x}{x-3}+\frac{x}{x+3}}$<br />mà ${x^2-9}$ = $(x+3)(x-3)$<br /><span>    </span>A = $\Large{\frac{6x}{(x+3)(x-3)}+\frac{5x(x+3)}{(x+3)(x-3)}+\frac{x(x-3)}{(x+3)(x-3)}}$<br /><span>    </span>= $\Large{\frac{6x}{(x+3)(x-3)}+\frac{5x^2 +15x }{(x+3)(x-3)}+\frac{x^2 -3x }{(x+3)(x-3)}}$  <br /><span>    </span>= $\Large{\frac{6x + 5x^2 +15x + x^2 -3x }{(x+3)(x-3)}}$   <br /><span>    </span>= $\Large{\frac{5x^2 + x^2 + 15x + 6x  -3x }{(x+3)(x-3)}}$   <br /><span>    </span>= $\Large{\frac{6x^2 + 18x}{(x+3)(x-3)}}$  <br /><span>    </span>= $\Large{\frac{6x(x + 3)}{(x+3)(x-3)}}$<br /><span>    </span>= $\Large{\frac{6x}{x-3}}$<br /><br />9) $5xy(2x^2 - xy) + (10x^3y^3 + 15x^4y^2 - 5xy): (5xy)$<br /><span>    </span>A = $5xy(2x^2 - xy) + (10x^3y^3 + 15x^4y^2 - 5xy): (5xy)$<br /><span>    </span>$(10x^3y^3 + 15x^4y^2 - 5xy): (5xy)$ <br /><span>    </span>= $5xy(x^2y^2 + 3x^3y -1) : (5xy)$<br />Triệt tiêu 5xy<br /><span>    </span>= $x^2y^2 + 3x^3y -1$<br /><span>    </span>A = $5xy(2x^2 - xy)  + x^2y^2 + 3x^3y -1$<br /><span>    </span>A = $10x^3y - 5x^2y^2  + x^2y^2 + 3x^3y -1$<br /><span>    </span>A = $13x^3y - 4x^2y^2 - 1$<br /><br />10) $\Large{\frac{3x-1}{x+2}+\frac{2x+11}{x+2}}$    <br /><span>    </span>A = $\Large{\frac{3x-1}{x+2}+\frac{2x+11}{x+2}}$ <br /><span>    </span>A = $\Large{\frac{3x-1 + 2x+11}{x+2}}$<br /><span>    </span>A = $\Large{\frac{5x +10}{x+2}}$ <br /><span>    </span>A = $\Large{\frac{5(x +2)}{x+2}}$ <br />Triệt tiêu x + 2<br /><span>    </span>A = 5<br /><br />11) $(2x - 1)^2+ (4x + 2)(1 - x)$<br /><span>    </span>A = $(4x^2 - 4x +1) + (4x - 4x^2 + 2 - 2x)$<br /><span>    </span>A = $4x^2 - 4x +1 + 4x - 4x^2 + 2 - 2x$ <br /><span>    </span>A = $ 4x^2 - 4x^2 - 4x + 4x - 2x +1 + 2$     A = $-2x +3 $<br /><br />12) $3x^2y(x^2 - 4y) + (30x^5y^3 - 25x^3y^4 - 5xy^2) : 5xy^2$ </div><div><span>    </span>A = $3x^2y(x^2 - 4y) + (30x^5y^3 - 25x^3y^4 - 5xy^2) : 5xy^2$<br /><span>    </span>A = $(3x^4y - 12x^2y^2) + 5xy^2(6x^4y - 5x^2y^2 - 1) : 5xy^2$<br /><span>    </span>A = $(3x^4y - 12x^2y^2) + (6x^4y - 5x^2y^2 - 1) $<br /><span>    </span>A = $3x^4y - 12x^2y^2 + 6x^4y - 5x^2y^2 - 1 $<br /><span>    </span>A = $3x^4y + 6x^4y - 12x^2y^2 - 5x^2y^2 - 1 $<br /><span>    </span>A = $9x^4y - 17x^2y^2 - 1 $<br /><br />13) $\Large{\frac{11x}{2x-3}+ \frac{x-18}{2x-3}}$<br />     <span>    </span>A = $\Large{\frac{11x}{2x-3}+ \frac{x-18}{2x-3}}$<br />     <span>    </span>A = $\Large{\frac{11x + x - 18}{2x - 3}}$<br />    <span>    </span>A = $\Large{\frac{12x - 18}{2x - 3}}$<br />    <span>    </span>A = $\Large{\frac{6(x - 3)}{2x - 3}}$<br />Triệt tiêu 2x - 3<br />    <span>    </span>A = 6<br /><br />14) $(3x + 2)(3x - 2) + 9x(1 - x)$<br /><span style="font-size: x-small;">    1. Use Difference of Squares: $a2−b2=(a+b)(a−b)$.<br /></span>        <span>    </span>$(3x)^2 − 2^2 + 9x(1 − x)$<br /><span style="font-size: x-small;">    2. Expand by distributing terms. <br /></span>        <span>    </span>$(3x)^2 – 2^2 + 9x − 9x^2$<br /><span style="font-size: x-small;">    3. Use Multiplication Distributive Property: $(xy)a=xaya$. <br /></span>        <span>    </span>$3^2x^2 − 2^2 + 9x − 9x^2$<br /><span style="font-size: x-small;">    4. Simplify $3^2$ to 9. <br /></span>        <span>    </span>$9x^2 – 2^2 + 9x − 9x^2$<br /><span style="font-size: x-small;">    5. Simplify $2^2$ to 4. <br /></span>        <span>    </span>$9x^2 – 4 + 9x − 9x^2$<br /><span style="font-size: x-small;">    6. Collect like terms. <br /></span>        <span>    </span>$(9x^2 − 9x^2) – 4 + 9x$<br /><span style="font-size: x-small;">    7. Simplify. <br /></span>        <span>    </span>$−4 + 9x$<br /><span style="font-size: x-small;">    8. Regroup terms. <br /></span>        <span>    </span>$9x − 4$<br /><br />15) $\Large{\frac{x}{x+2}-\frac{3}{x-2}-\frac{x^2+9}{x^2-4}}$<br />     <span><span>    </span>    </span>$x^2 - 4 = (x - 2)(x + 2)$<br />    <span>    </span>A = $\Large{\frac{x}{x+2}-\frac{3}{x-2}-\frac{x^2+9}{x^2-4}}$<br />     <span>    </span>A = $\Large{\frac{x(x-2) - 3(x+2) - (x^2+9)}{(x - 2)(x + 2)}}$<br />    <span>    </span>A = $\Large{\frac{x^2 - 2x - 3x - 6 - x^2 - 9)}{(x - 2)(x + 2)}}$<br />    <span>    </span>A = $\Large{\frac{x^2 - x^2 - 2x - 3x - 6 - 9}{(x - 2)(x + 2)}}$<br />    <span>    </span>A = $\Large{\frac{ - 5x  - 15}{(x - 2)(x + 2)}}$<br />    <span>    </span>A = $\Large{\frac{ - 5(x  + 3)}{(x - 2)(x + 2)}}$<br /><br />16) $4x^2y(2xy^2 - xy)+ (25x^4y^3 - 10x^4y^4 + 5xy): (5xy)$<br />    <span>    </span>A = $4x^2y(2xy^2 - xy)+ (25x^4y^3 - 10x^4y^4 + 5xy): (5xy)$<br />    <span>    </span>A = $(8x^3y^3 - 4x^3y^3)+ (5xy(5x^3y^2 - 2x^3y^3 + 1)): (5xy)$<br />    <span>    </span>A = $8x^3y^3 - 4x^3y^3+ 5x^3y^2 - 2x^3y^3 + 1$ </div><div><span>    </span>A = $8x^3y^3 - 4x^3y^3 - 2x^3y^3 + 5x^3y^2 + 1$<br />     <span>    </span>A = $8x^3y^3 - 4x^3y^3 - 2x^3y^3 + 5x^3y^2 + 1$<br />    <span>    </span>A = $2x^3y^3 + 5x^3y^2 + 1$<br /><br />17) $\Large{\frac{2x-4}{3x+2}+\frac{3x+1}{3x+2}}$<br /><span>    </span>A = $\Large{\frac{2x-4}{3x+2}+\frac{3x+1}{3x+2}}$<br /><span>    </span>A = $\Large{\frac{2x - 4 + 3x+1}{3x+2}}$<br /><span>    </span>A = $\Large{\frac{5x - 3}{3x+2}}$<br /><br />18) $(x - 6)^2 + (x + 7)(4 - x)$<br /><span>    </span>A = $(x - 6)^2 + (x + 7)(4 - x)$<br /><span>    </span>A = $(x^2 - 12x + 36) + (4x - x^2 +28 - 7x)$<br /><span>    </span>A = $x^2 - 12x + 36 + 4x - x^2 +28 - 7x$ </div><div><span>    </span> A = $x^2 - x^2- 12x + 4x - 7x + 36 +28 $<br />     <span>    </span>A = $- 15x + 60 $<br />     <span>    </span>A = $- 15(x - 4) $<br /><br />19) $\Large{\frac{1-3x}{2x}+\frac{3x-2}{2x-1}-\frac{3x-2}{4x^2-2x}}$<br />    <span>    </span>A = $\Large{\frac{1-3x}{2x}+\frac{3x-2}{2x-1}-\frac{3x-2}{4x^2-2x}}$<br /><span>    </span>$4x^2-2x = 2x(2x -1)$ </div><div><span>    </span>A = $\Large{\frac{(1-3x)(2x -1)}{2x(2x -1)}+\frac{2x(3x-2)}{2x(2x-1)}-\frac{3x-2}{2x(2x -1)}}$</div><div><span>    </span>A = $\Large{\frac{(1-3x)(2x -1) + 2x(3x-2) - (3x-2)}{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{(2x -1 - 6x^2 + 3x) + (6x^2 - 4x) - (3x-2)}{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{2x -1 - 6x^2 + 3x + 6x^2 - 4x - 3x + 2}{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{ - 6x^2 + 6x^2+ 3x + 2x - 4x - 3x + 2  -1}{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{ (- 6x^2 + 6x^2)+ (3x + 2x - 4x - 3x) + (2  -1)}{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{- 2x + 1 }{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{- (2x - 1) }{2x(2x -1)}}$<br />    <span>    </span>A = $\Large{\frac{- 1 }{2x }}$<br /><br />20) $2xy(2x - xy^2) + (3x^4y^4 - 9x^4y^2 + 6x^2y): (3x^2y)$<br /><span>    </span>A = $2xy(2x - xy^2) + (3x^4y^4 - 9x^4y^2 + 6x^2y): (3x^2y)$<br /><span>    </span>A = $(4x^2y - 2x^2y^3) + (3x^2y(x^2y^3 - 3x^2y + 2): (3x^2y)$<br />Triệt tiêu $3x^2y$<br /><span>    </span>A = $(4x^2y - 2x^2y^3) + (x^2y^3 - 3x^2y + 2)$<br /><span>    </span>A = $4x^2y - 2x^2y^3 + x^2y^3 - 3x^2y + 2$     A = $ 4x^2y - 3x^2y + x^2y^3 - 2x^2y^3 + 2$<br /><span>    </span>A = $- x^2y^3 + x^2y + 2$<br /><br />21) $\Large{\frac{x+2}{x-1}+\frac{3x+1}{x-1}}$<br /><span>    </span>A = $\Large{\frac{x+2}{x-1}+\frac{3x+1}{x-1}}$<br /><span>    </span>A = $\Large{\frac{x + 2 + 3x + 1}{x-1}}$<br /><span>    </span>A = $\Large{\frac{5x + 3}{x-1}}$<br /><span>    </span>A = $27x -3$<br /><br />22) $5x(5 - x) + (x + 1)(5x - 3)$<br /><span>    </span>A = $5x(5 - x) + (x + 1)(5x - 3)$<br /><span>    </span>A = $(25x - 5x^2) + (5x^2 - 3x + 5x -3 )$<br /><span>    </span>A = $25x - 5x^2 + 5x^2 - 3x + 5x -3 $<br /><span>    </span>A = $5x^2 - 5x^2 + 25x + 5x - 3x -3 $<br /><span>    </span>A = $27x -3 $    <br /><br />23) $\Large{\frac{x}{x-2}-\frac{x}{x+2}-\frac{8}{x^2-4}}$<br /><span>    </span>$x^2 - 4 = (x -2 ) (x + 2)$    A = $\Large{\frac{x}{x-2}-\frac{x}{x+2}-\frac{8}{ (x -2 ) (x + 2)}}$<br /><span>    </span>A = $\Large{\frac{x(x+2) - x(x-2) - 8}{ (x -2 ) (x + 2)}}$<br /><span>    </span>A = $\Large{\frac{x^2 + 2x - x^2 + 2x - 8}{ (x -2 ) (x + 2)}}$<br /><span>    </span>A = $\Large{\frac{x^2 - x^2 + 2x + 2x - 8}{ (x -2 ) (x + 2)}}$<br /><span>    </span>A = $\Large{\frac{ 4x - 8}{ (x -2 ) (x + 2)}}$<br /><span>    </span>A = $\Large{\frac{ 4(x - 2)}{ (x -2 ) (x + 2)}}$<br />Triệt tiêu x-2<br /><span>    </span>A = $\Large{\frac{ 4}{ x + 2}}$<br /><br />24) $3y^2(2x^2 + xy) + (9x^2y^5 + 6x^3y^4 - 12xy^2): 3xy^2$    A </div><div><span>    </span>= $(6x^2y^2 + 3xy^3) + (9x^2y^5 + 6x^3y^4 - 12xy^2): 3xy^2$<br /><span>    </span>$(9x^2y^5 + 6x^3y^4 - 12xy^2): 3xy^2$<br /><span>    </span>= $3xy^2 (3xy^3 + 2x^2y^2 - 4): 3xy^2$<br />Triệt tiêu $3xy^2$<br /><span>    </span>= $3xy^4 + 2x^2y^3 - 4$<br /><span>    </span>A = $3y^2(2x^2 + xy) + 3xy^4 + 2x^2y^3 - 4$<br /><span>    </span>A = $6x^2y^2 + 3xy^3 + 3xy^4 + 2x^2y^3 - 4$<br /><span>    </span>A = $6x^2y^2 + 3xy^3 + 3xy^4 + 2x^2y^3 - 4$<br /><br />25) $\Large{\frac{2x+3}{x+1}+\frac{3x-1}{x+1}}$<br /><span>    </span>A = $\Large{\frac{(2x+3)+(3x-1)}{x+1}}$<br /><span>    </span>A = $\Large{\frac{2x+3+3x-1}{x+1}}$<br /><span>    </span>A = $\Large{\frac{5x+2}{x+1}}$<br /><br />26) $(2x - 5)(2x + 5) - (1 - 2x)^2 - 4x$<br /><span>    </span>A = $(2x - 5)(2x + 5) - (1 - 2x)^2 - 4x$<br /><span>    </span>A = $((2x)^2 - 5^2) - (1 - 2x)^2 - 4x$<br /><span>    </span>A = $(4x^2 - 25) - (1^2 - 2.1.2x + (2x)^2 ) - 4x$<br /><span>    </span>A = $4x^2 - 25 - 1^2 + 2.1.2x - (2x)^2 - 4x$<br /><span>    </span>A = $4x^2 - 25 - 1^2 + 2.1.2x - (2x)^2 - 4x$<br /><span>    </span>A = $4x^2 - 25 - 1 + 4x - 4x^2 - 4x$    A = $(4x^2 - 4x^2) + (4x - 4x) - 25 - 1$<br />     <span>    </span>A = $- 25 - 1$<br />     <span>    </span>A = $ - 26$<br /><br />27) $\Large{\frac{2}{x+1}+\frac{4}{x-1}-\frac{5x+1}{x^2-1}}$<br /><span>    </span>$x^2-1$ = $x^2-1^2$ = $(x-1)(x+1)$ <br /><span>    </span>A = $\Large{\frac{2}{x+1}+\frac{4}{x-1}-\frac{5x+1}{x^2-1}}$<br /><span>    </span>A = $\Large{\frac{2(x-1) + 4(x+1) - (5x+1)}{(x-1)(x+1)}}$<br /><span>    </span>A = $\Large{\frac{2x - 2 + 4x + 4 - 5x -1}{(x-1)(x+1)}}$    A </div><div><span>    </span>= $\Large{\frac{2x + 4x - 5x - 2 + 4 -1}{(x-1)(x+1)}}$<br /><span>    </span>A = $\Large{\frac{x +1}{(x-1)(x+1)}}$<br /><span>    </span>A = $\Large{\frac{x +1}{(x-1)(x+1)}}$<br />Triệt tiêu x + 1<br />    <span>    </span>A = $\Large{\frac{1}{(x - 1)}}$<br /><br />28) $5xy(4x^2 - xy) + (4x^5y^2 - 8x^4y^3 + 16x^2y): (4x^2y)$<br /><span>    </span>$(4x^5y^2 - 8x^4y^3 + 16x^2y): (4x^2y) </div><div><span>    </span>= 4x^2y(x^3y - 2x^2y^2 + 4): (4x^2y)$</div><div>Triệt tiêu $(4x^2y)$    = $x^3y - 2x^2y^2 + 4$<br /><span>    </span>A = $5xy(4x^2 - xy) + (4x^5y^2 - 8x^4y^3 + 16x^2y): (4x^2y)$<br /><span>    </span>A = $5xy(4x^2 - xy) + x^3y - 2x^2y^2 + 4$<br /><span>    </span>A = $(20x^3y - 5x^2y^2) + x^3y - 2x^2y^2 + 4$<br /><span>    </span>A = $20x^3y - 5x^2y^2 + x^3y - 2x^2y^2 + 4$<br /><span>    </span>A = $(20x^3y + x^3y)- (5x^2y^2 + 2x^2y^2) + 4$<br /><span>    </span>A = $21x^3y - 7x^2y^2 + 4$<br /><br />29) $\Large{\frac{2x-1}{3x-2}+\frac{x+3}{3x-2}}$ </div><div><span>    </span> A = $\Large{\frac{2x-1}{3x-2}+\frac{x+3}{3x-2}}$<br /><span>    </span>A = $\Large{\frac{(2x-1)+(x+3)}{3x-2}}$<br /><span>    </span>A = $\Large{\frac{2x-1+x+3}{3x-2}}$<br />    <span>    </span>A = $\Large{\frac{3x+2}{3x-2}}$<br /><br />30) $(x + 5)^2 - (x + 3). (x - 2)$<br />    <span>    </span>A = $(x + 5)^2 - (x + 3). (x - 2)$<br /><span>    </span>A = $(x^2 + 2.5.x + 5^2) - (x^2 - 2x + 3x - 6)$<br /><span>    </span>A = $x^2 + 2.5.x + 5^2 - x^2 + 2x - 3x + 6$<br /><span>    </span>A = $(x^2 - x^2) + (2.5.x + 2x - 3x) + (5^2 + 6)$<br /><span>    </span>A = $ 9x + 31$<br /><br />31) $\Large{\frac{1}{x+2}+\frac{2}{x-2}-\frac{2x}{x^2-4}}$ </div><div> <span>    </span>$x^2 - 4$ = $x^2 - 2^2$ = $(x - 2)(x + 2)$<br /><span>    </span>A = $\Large{\frac{1}{x+2}+\frac{2}{x-2}-\frac{2x}{x^2-4}}$<br /><span>    </span>A = $\Large{\frac{1(x - 2) + 2(x + 2) - 2x}{(x - 2)(x + 2)}}$<br />    <span>    </span>A = $\Large{\frac{x - 2 + 2x + 4 -2x}{(x - 2)(x + 2)}}$<br /><span>    </span>A = $\Large{\frac{x + 2}{(x - 2)(x + 2)}}$<br />    Triệt tiêu x +2<br />     <span>    </span>A = $\Large{\frac{1}{(x - 2)}}$<br /><br />32) $\Large{\frac{x^2 - 1}{x^2 + 4x}.\frac{2x}{x - 1}}$<br /><span>    </span>A = $\Large{\frac{x^2 - 1}{x^2 + 4x}.\frac{2x}{x - 1}}$ </div><div><span>    </span>A = $\Large{\frac{(x^2 - 1)2x}{(x^2 + 4x)(x - 1)}}$<br /><span>    </span>A = $\Large{\frac{2x^3 - 2x}{x^3 - x^2 + 4x^2 - 4x}}$<br /><span>    </span>A = $\Large{\frac{2x^3 - 2x}{x^3  + 3x^2 - 4x}}$<br /><span>    </span>A = $\Large{\frac{2x(x^2 - 1)}{x(x^2  + 3x - 4)}}$<br />Triệt tiêu x<br /><span>    </span>A = $\Large{\frac{2(x^2 - 1)}{(x^2  + 3x - 4)}}$<br /><br />33) $\Large{\frac{x+y}{xy}+\frac{x-2}{xy}+\frac{x-14}{x^2-4}}$ </div><div> <span>    </span>$x^2-4  = x^2 - 2^2$ = $(x+2)(x-2)$ </div><div><span>    </span> A = $\Large{\frac{x+y}{xy}+\frac{x-2}{xy}+\frac{x-14}{x^2-4}}$<br />     <span>    </span>A = $\Large{\frac{x+y}{xy}+\frac{x-2}{xy}+\frac{x-14}{x^2 - 2^2}}$<br />     <span>    </span>A = $\Large{\frac{x+y}{xy}+\frac{x-2}{xy}+\frac{x-14}{(x+2)(x-2)}}$<br />MTC: $xy(x+2)(x-2)$<br />     <span>    </span>A = $\Large{\frac{(x+y)(x+2)(x-2)+(x-2)(x+2)(x-2)+(x-14)xy}{xy(x+2)(x-2)}}$<br />$x^ax^b = x^ab$<br />    <span>    </span>A = $\Large{\frac{(x+y)(x+2)(x-2)+((x-2)(x-2))(x+2)+(x-14)xy}{xy(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{(x+y)(x+2)(x-2)+(x-2)^2(x+2)+(x-14)xy}{xy(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{x^3−2x^2+2x^2−4x+yx^2−2yx+2yx−4y+x3+2x^2−4x^2−8x+4x+8+x2y−14xy}{xy(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{(x^3+x^3)+(−2x^2+2x^2+2x^2−4x^2)+(−4x−8x+4x)+(x^2y+x^2y)+(−2xy+2xy−14xy)−4y+8}{xy(x+2)(x-2)}}$ $(x^3+x^3)+(−2x^2+2x^2+2x^2−4x^2)+(−4x−8x+4x)+(x^2y+x^2y)+(−2xy+2xy−14xy)−4y+8$<br /> <span>    </span>= $2x^3−2x^2−8x+2x^2y−14xy−4y+8$<br />    <span>    </span>A = $\Large{\frac{2x^3−2x^2−8x+2x^2y−14xy−4y+8}{xy(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{2(x^3−x^2−4x+x^2y−7xy−2y+4)}{xy(x+2)(x-2)}}$<br /><br />34) $\Large{\frac{x+1}{x-2}-\frac{x-2}{x+2}+\frac{x-14}{x^2-4}}$</div><div><span>    </span>$x^2-4 = x^2-2^2=(x+2)(x-2)$<br />    <span>    </span>A = $\Large{\frac{x+1}{x-2}-\frac{x-2}{x+2}+\frac{x-14}{x^2-4}}$<br />    <span>    </span>A = $\Large{\frac{x+1}{x-2}-\frac{x-2}{x+2}+\frac{x-14}{(x+2)(x-2)}}$ </div><div><span>    </span> A = $\Large{\frac{(x+1)(x+2)−(x−2)(x−2)+x−14}{(x+2)(x-2)}}$<br /><span>    </span>$x^ax^b=x^{a+b}.$<br />    <span>    </span>A = $\Large{\frac{(x+1)(x+2)−(x−2)^2+x−14}{(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{x^2+2x+x+2−x^2+2x.2−2^2+x−14}{(x+2)(x-2)}}$<br /><span>    </span>$2^2 = 4$    A = $\Large{\frac{x^2+2x+x+2−x^2+2x.2−4+x−14}{(x+2)(x-2)}}$<br /><span>    </span>$2x.2=4x$<br />    <span>    </span>A = $\Large{\frac{x^2+2x+x+2−x^2+4x−4+x−14}{(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{(x^2−x^2)+(2x+x+4x+x)+(2−4−14)}{(x+2)(x-2)}}$<br /><span>    </span>$(x^2−x^2)+(2x+x+4x+x)+(2−4−14) = 8x−16$<br />    <span>    </span>A = $\Large{\frac{8x−16}{(x+2)(x-2)}}$<br />    <span>    </span>A = $\Large{\frac{8(x−2)}{(x+2)(x-2)}}$<br />Triệt tiêu x-2<br />    <span>    </span>A = $\Large{\frac{8 }{(x+2) }}$<br /><br />35) $\Large{\frac{1}{x+5}-\frac{1}{x-5}+\frac{2x}{x^2-25}}$$a^2-b^2; a=x, b=5$<br /><span>    </span>$x^2-25 = x^2-5^2=(x+5)(x-5)$    A = $\Large{\frac{1}{x+5}-\frac{1}{x-5}+\frac{2x}{x^2-25}}$    <br />    <span>    </span>A = $\Large{\frac{1}{x+5}-\frac{1}{x-5}+\frac{2x}{(x+5)(x-5)}}$<br />    <span>    </span>A = $\Large{\frac{x−5−(x+5)+2x}{(x+5)(x-5)}}$<br />    <span>    </span>A = $\Large{\frac{x−5−x-5+2x}{(x+5)(x-5)}}$<br />    <span>    </span>A = $\Large{\frac{(x−x+2x)+(−5−5)}{(x+5)(x-5)}}$<br />    <span>    </span>A = $\Large{\frac{(2x-10)}{(x+5)(x-5)}}$<br />    <span>    </span>A = $\Large{\frac{(2(x-5))}{(x+5)(x-5)}}$<br />Triệt tiêu x-5<br />    <span>    </span>A = $\Large{\frac{2)}{x+5}}$<br /><br />36) $6xy(2x^2 -3y)+(4x^2y^3 – 2x^4y^3 – 2x^4y^2 + 3xy):(xy)$ ?<br /><br /><br />37) $\Large{\frac{a^2+2b}{a+3}+\frac{3a-2b}{a+3}}$<br />    <span>    </span>A = $\Large{\frac{a^2+2b}{a+3}+\frac{3a-2b}{a+3}}$</div><div><span>    </span>A = $\Large{\frac{a^2+2b+3a−2b}{a+3}}$<br />    <span>    </span>A = $\Large{\frac{a(a+3)}{a+3}}$    A = a<br /><br />38) $(3x +1)^2 –(3x -2)(3x + 4)$$(a+b)^2=a^2+2ab+b^2$<br />    <span>    </span>A = $(3x +1)^2 –(3x -2)(3x + 4)$<br />    <span>    </span>A = $(3x)^2+2×3x+1−(3x−2)(3x+4)$<br />    <span>    </span>A = $(3x)^2+2×3x+1−(9x^2+12x−6x−8)$<br />    <span>    </span>A = $(3x)^2+2×3x+1−9x^2-12x+6x+8)$<br /><span>    </span>$(xy)^a=x^ay^a.$<br />    <span>    </span>A = $32x^2+2×3x+1−9x^2−12x+6x+8$<br /><span>    </span>$3^2=9$<br />    <span>    </span>A = $9x^2+2×3x+1−9x^2−12x+6x+8$<br /><span>    </span>$2.3x = 6x$<br />    <span>    </span>A = $9x^2+6x+1−9x^2−12x+6x+8$<br />    <span>    </span>A = $(9x^2−9x^2)+(6x−12x+6x)+(1+8)$<br />    <span>    </span>A = 9<br /><br />39) $\Large{\frac{x+1}{x-2}+\frac{4}{x+2}+\frac{2-7x}{x^2-4}}$</div><div><span>    </span>$a^2 - b^2 =(a+b)(a-b)$<br /><span>    </span>a = x; b = 2<br /><span>    </span>$x^2 − 2^2 = (x + 2)(x - 2)$$\Large{\frac{x+1}{x−2}+\frac{4x}{x+2}+\frac{2−7x}{x^2−2^2}}$<br /><span>    </span>$\Large{\frac{x+1}{x−2}+\frac{4x}{x+2}+\frac{2−7x}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{(x+1)(x+2)+4x(x−2)+2−7x}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{(x+1)(x+2)+4x(x−2)+2−7x}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{x^2+2x+x+2+4x^2−8x+2−7x}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{(x^2+4x^2)+(2x+x−8x−7x)+(2+2)}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{(5x^2−12x+4}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{5x^2−2x−10x+4}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{5x^2−2x−10x+4}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{x(5x−2)−2(5x−2)}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{(5x−2)(x−2)}{(x + 2)(x - 2)}}$<br /><span>    </span>$\Large{\frac{5x−2}{(x + 2)(x - 2)}}$<br /><br />40) $5a^2b(2a - ab^2) + (9a^5b^5 – 12a^5b^3 + 15a^2b^2): (3a^2b^2)$<br /><br />41) $\Large{\frac{5x-2}{4x+12}+\frac{x+9}{4x+12}}$<br /><br />42) $(2x + l)^2 - (2x + 3)(x - 1)$<br /><br />43) $\Large{\frac{1}{x+5}+\frac{6}{x-5}-\frac{2x}{x^2-25}}$<br /><br />44) $3x (2x^2y+ 3xy) + (6x^4y^2 - 8x^3y^2 + 4xy) : (2xy)$<br /><br />45) $\Large{\frac{x^2-2x}{x+3}:\frac{x^2-4}{x^2+3x}}$<br /><br />46) $(x - 3)(x + 3) + (x - 5)^2 - 2x(x - 5)$<br /><br />47) $\Large{\frac{5x+6}{x^2-4}+\frac{2}{x+2}-\frac{4}{x-2}}$<br /><br /><br />---------------------------------</div></div><div class="separator" style="clear: both; text-align: center;"><br /></div><br /></div></div><div class="separator" style="clear: both; text-align: center;"><br /></div><br />

Thực hiện các phép tính sau:

DẠNG THỰC HIỆN PHÉP TÍNH 1) $\Large{\frac{4xy(2x^2 - xy) + (8x^3y3 - 6x^4y^2 + 2xy)}{(2xy)}}$ $\Large{\frac{4xy(2x^2-xy)+(8x^3y^3 - 6x^...

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VIII/ LISTENING

<p> </p>
<div class="box-question">
<div class="question">
<h3> <b>  30. The boy is preparing his house for______________. </b> </h3>
<ul>
<li class="correct"> a storm </li>	
<li> a high wind </li>
 <li> a flood	 </li>	
<li> damage from falling trees </li>
</ul>
<p>  </p>
<h3><b> 31. The girl ______________. </b> </h3>
<ul>
<li> heard about the emergency on the radio </li>	
<li> missed the emergency warning on the radio </li>
 <li> does not think there will be an emergency </li>	
<li class="correct"> did not know anything about an emergency </li>
</ul>
<p>  </p>
<h3><b> 32. Why are the boy’s parents not stocking up on food?</b></h3>
<ul>
 <li> There isn’t time to get to the store. </li>	
<li class="correct"> The emergency will not last very long. </li>
 <li> There is no food left in the store.	 </li>	
<li> They already have a lot of food in case of an emergency. </li>
</ul>
<p>  </p>
<h3><b> 33. How fast do typhoons move across land, according to the boy? </b></h3>
<ul>
<li> 20 kph </li>	
<li class="correct"> 30 kph </li>
 <li> 200 kph </li>	
<li> 300 kph </li>
</ul>
<p>  </p>
<h3><b> 34. What does the boy tell the girl to do? </b></h3>
<ul>
<li class="correct"> Wait to see if a warning comes on the radio </li>	
<li> Inform her parents about the emergency immediately </li>
 <li> Stay at his house </li>	
<li> Go and board up the windows of her house </li>
</ul>
<p>  </p>
  <b>4C- Listen to the conversation between Jessica and kita. L irclc the cot reel answers. (5 questions)</b>
<h3><b> Câu 6: </b></h3>
<ul>
<li> 6A </li>
<li> 6B </li>
<li class="correct"> 6G </li>	
 <li> 6C </li>	</ul>
<h3><b> Câu 7: </b></h3>
<ul>
<li> 7B </li>	
<li> 7A </li>
<li> 7c </li>	 
<li class="correct"> 7G </li>
</ul>
<p>  </p>
<h3><b> Câu 8: </b></h3>
<ul>
<li> 8A </li>	
<li class="correct"> 8G </li>
 <li> 8B </li>	
<li> 8C </li>
</ul>
<p>  </p>
<h3><b> Câu 9: </b></h3>
<ul>
<li> 9A </li>	
<li> 10C </li>
 <li> 10B </li>	
<li class="correct"> 9G </li>
</ul>
<p>  </p>
<h3><b> Câu 10: </b></h3>
<ul>
 <li> 10C </li>	
<li> 10A </li>
  <li> 10B </li>	 
 <li class="correct"> 10G </li>
</ul>
<p>  </p>
<h3> <b>  Câu 11: </b> </h3>
<ul>
<li> 1A </li>	
<li> 1C </li>
 <li> 1B </li>	
<li class="correct"> 1G </li>
</ul>
<p>  </p>
<h3><b> Câu 12: </b> </h3>
<ul>
<li> 2B </li>	
<li> 2C </li>
 <li class="correct"> 2G </li>	
<li> 2A </li>
</ul>
<p>  </p>
<h3><b> Câu 13: </b></h3>
<ul>
<li> 3C </li>	
<li> 3A </li>
 <li> 3B </li>	
<li class="correct"> 3G </li>
</ul>
<p>  </p>
<h3><b> Câu 14: </b></h3>
<ul>
<li> 4C </li>	
<li> 4A </li>
 <li> 4B </li>	
<li class="correct"> 4G </li>
</ul>
<p>  </p>
<h3><b> Câu 15: </b></h3>
<ul>
<li> 5B </li>	
<li class="correct"> 5G </li>
 <li> 5A </li>	<li> 5C </li></ul>
<p>  </p>
<h3><b> Câu 16: </b></h3>
<ul>
<li> 6A </li>
<li> 6B </li>  
<li> 6C </li>	   	 	 
<li class="correct"> 6G </li></ul>
<p>  </p>
<h3><b> Câu 17: </b></h3>
<ul>
<li> 7A </li>	
<li class="correct"> 7G </li>
 <li> 7C </li>	
<li> 7B </li>
</ul>
<p>  </p>
<h3><b> Câu 18: </b></h3>
<ul>
<li class="correct"> 8G </li>	
<li> 8C </li>
 <li> 8B </li>	
<li> 8A </li>
</ul>
<p>  </p>
<h3><b> Câu 19: </b></h3>
<ul>
<li> 9C </li>	
<li class="correct"> 9G </li>
 <li> 9A </li>	
<li> 9B </li>
</ul>
<p>  </p>
<h3><b> Câu 20: </b></h3>
<ul>
<li> 19A </li>	
<li class="correct"> 19G </li>
 <li> 19C </li>	
<li> 19B </li>
</ul>
<p>  </p>

</div>
<div class="result"><span class="message"> Hãy trả lời các câu hỏi để biết kết quả của bạn </span></div>
</div>

VIII/ LISTENING

30. The boy is preparing his house for______________. a storm a high wind a flood damage from falling trees 31. ...

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VII/ Read the passage and then decide whether the sentences are True or False

<div style="text-align: justify;"><span style="color: red; font-size: medium;"><b>TEXT A </b></span></div><div style="text-align: justify;"><span style="color: #2b00fe; font-size: medium;"><b>-WHAT IS A TSUNAMI </b></span></div><div style="text-align: justify;"><span style="font-size: medium;"><br /></span></div><div style="text-align: justify;"><span style="font-size: medium;"><span>    </span><span style="font-family: times;">A tsunami is a string of large ocean waves. Some people call it a “wave train" or a "tidal wave." Tsunamis, unlike normal ocean waves, are not caused by tides. The word tsunami comes from the Japanese. Tsunamis are caused by a sudden, large motion on the ocean floor. They can be caused by an earthquake under the ocean. Sometimes an underwater landslide or volcano is the cause. When one of these tilings happens, the energy passes through the ocean water. Just like the ripples from a rock being thrown into a pond, the energy released by one of these motions spreads One in all directions. </span></span></div><div style="text-align: justify;"><span style="font-family: times; font-size: medium;"><span>    </span>The energy can travel many miles away. Tsunamis move at high speeds. Most tsunamis happen in the Pacific Ocean. In the deep walers, a tsunami may travel -150 miles per hour. Out in the ocean, a tsunami may be hard to see. As it comes close to shore, its speed slows down. The height of the wave builds. The tsunami may suddenly rise into a wave ten to one hundred feet high. These large waves are a disaster for coastal regions and people living there. Tsunami warning networks alert people living along coastlines in the Pacific Ocean. When a warning is sounded, people can move away from the coast to higher ground. The wavelength can be as long as 150 miles. This means the time (wave period) between the giant waves is long, too. Giant waves on shore call last for hours or even days alter the earthquake or other disturbance.</span><span style="font-size: medium;"><b> (</b></span><span style="background-color: white; color: #333333; font-family: times; text-align: left;">(<b><i>TA8.Unit 4</i></b>))</span></div><div style="text-align: justify;"><span style="font-size: medium;"><b><br /></b></span></div><div style="text-align: justify;"><span style="font-family: times; font-size: medium;"><b>1. "Wave train" or "tidal wave" is another term for tsunami.  </b></span></div><span style="font-size: medium;"><div>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;">1. => Thông tin: Some people call it a “wave train" or a "tidal wave.</span>
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<div><br /></div>
<span style="font-size: medium;"><span style="font-family: times;"><b> 2. Tsunamis often come from Japan.   </b>
</span><div>
<div>
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<div style="background: #; border: 1px solid rgb(79, 79, 79); display: none; padding: 4px;">
<span style="font-size: medium;"> 2. => Thông tin: The word tsunami comes from the Japanese

</span>
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</div></div>
<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 3. A tsunami may be hard to see because it may travel 450 miles per hour.

</b>
</span><div>
<div>
<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<span style="font-size: medium;"> 3. => Thông tin: In the deep waters, a tsunami may travel 450 miles per hour. Out in the ocean, a tsunami may be hard to see.

</span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b>4. Only people living along coastlines in the Pacific Ocean are alerted with tsunami warning networks.

</b>
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<span style="font-size: medium;"> 4. => Thông tin: Tsunami warning networks alert people living along coastlines in the Pacific Ocean.

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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 5. Big waves on shore can last very' long after the earthquake.

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<span style="font-size: medium;"> 5. => Thông tin: Giant waves on shore can last for hours or even days after the earthquake or other disturbance

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</div></div><div><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><br /></span></span></span></span></span></div><b><span style="color: red;">
  
  TEXT B </span></b></span></span></span></span></span><div style="text-align: justify;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="color: #2b00fe; font-size: medium;"><b>- Most of the time. </b></span></span></span></span></span></div><div style="text-align: justify;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span>    </span><span style="font-family: times;">I write about blizzards, typhoons, floods, and so on. But I don't ski in a blizzard or get wet in a flood. Well, this week's blog is different, because (his time I was there when something big happened! </span></span></span></span></span></span></div><div style="text-align: justify;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-family: times; font-size: medium;"><span>    </span> I was on holiday in an area which has earthquakes. I knew (hat before I went. But (he last big earthquake there happened 50 years ago. so I didn't really think about it when 1 booked. </span></span></span></span></span></div><div style="text-align: justify;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-family: times; font-size: medium;"><span>    </span> During the first few days. I went swimming every morning in the warm sea and then, in the afternoon, I walked up the side of the mountain behind the town. 1 didn't climb over rocks or anything like that. I just walked slowly up a few hundred meters on one of the old donkey tracks. </span></span></span></span></span></div><div><div style="text-align: justify;"><span style="font-size: large;">    </span><span style="font-family: times;"><span style="font-size: large;"> </span><span style="font-size: medium;">On the afternoon of the fifth day. I was on the mountain w hen the ground started to move. I remembered about the earthquakes then, and I thought, 'The ground will open up and i'll fall ill.' Then I looked down al the town and saw a huge wave coming very fast towards it. Houses near the beach disappeared under the water. I was safe on the side of the mountain, but my hotel fell down and I lost all my stuff.</span></span></div><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 1. The writer's blog is usually about had weather. </b>
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<span style="font-size: medium;"> <b>True</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b>2. The writer thought there might be an earthquake while he was there on holiday.</b>
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<span style="font-size: medium;"> <b>False</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 3. One of the donkey tracks went to the top of the mountain.  </b>
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<span style="font-size: medium;"> <b>Not given</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 4. The writer fell into a hole during the earthquake. </b>
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<span style="font-size: medium;"><b>False</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 5. The writer watched as the tsunami hit the town. </b>
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<input 1="" onclick="if (this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display != '') { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = '';this.innerText = ''; this.value = 'Ẩn'; } else { this.parentNode.parentNode.getElementsByTagName('div')[1].getElementsByTagName('div')[0].style.display = 'none'; this.innerText = ''; this.value = 'XEM'; }" style="font-size: 11px; margin: 0px; padding: 4px; width: 75px;" type="button" value="XEM" />
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<span style="font-size: medium;"> <b>True</b></span>
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   <b> (TiếngAnh 8 i-Learn Smart World_Unit 4.2. PART 5          READING (5 questions))</b> </span></span></span></span></span></span></span></span></span></span></div><div><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><br /></span></span></span></span></span></span></span></span></span></span></div><div><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><b><span style="color: red;"> <span style="font-family: times;">TEXT C</span></span></b><span style="font-family: times;"> </span></span></span></span></span></span></span></span></span></span></span></div><div><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="color: #2b00fe; font-family: times; font-size: medium;"><b>- The emergency announcement</b></span></span></span></span></span></span></span></span></span></span></div><div><div style="text-align: justify;"><ul><li><span style="font-family: times; font-size: medium;"> <span>   </span>Sent: 21:36 June 3 </span></li><li><span style="font-family: times; font-size: medium;"><span>    </span>What: A heat wave </span></li><li><span style="font-family: times; font-size: medium;"><span>    </span>Where: Oakland City </span></li><li><span style="font-family: times; font-size: medium;"><span>    </span>When: From 10:00 June 4 to 16:45 June 9 </span></li><li><span style="font-family: times; font-size: medium;"><span>    </span>The heat wave is now going on in the city. </span></li><li><span style="font-family: times; font-size: medium;"><span>    </span>The highest temperature may hit 40oC. </span></li></ul></div><div style="text-align: justify;"><span style="font-family: times; font-size: medium;"><span>    </span> People with weight and alcohol problems may gel heatstroke. 1 he heat wave might affect other systems across the city. Water and electricity shortage may happen during the heat wave. </span></div><div style="text-align: justify;"><span style="font-family: times; font-size: medium;"><span>    </span> <b>Instructions</b>: </span></div><div style="text-align: justify;"><ul><li><span style="font-family: times; font-size: medium;">Wear .1 hat or carry an umbrella with you It you re outùiuc. </span></li><li><span style="font-family: times; font-size: medium;">Get enough water and as Old Migary drink" </span></li><li><span style="font-family: times; font-size: medium;">Exercise gently. </span></li><li><span style="font-family: times; font-size: medium;">Come and see your family, friends and neighbors, especially older people. </span></li><li><span style="font-family: times; font-size: medium;">If someone gets heatstroke or heal exhaustion, contact the emergency ser\ ices immediately.</span></li></ul></div><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-size: medium;"><span style="font-family: times;"><b> 1. There are no power supplies and water during the heat wave. </b>
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<span style="font-size: medium;"> <b>False</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 2. Heatstroke is dangerous during the heal wave. </b>
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<span style="font-size: medium;"> <b>Not given</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 3. Bring an umbrella with you if you are out during the heat wave </b>
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<span style="font-size: medium;"> <b>True</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 4. Slay away from sugary drinks during the heal wave </b>
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<span style="font-size: medium;"> <b>True</b></span>
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<div><br /></div><span style="font-size: medium;"><span style="font-family: times;"><b> 5. Call an emergency service if someone suffers from heatstroke. </b>
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<span style="font-size: medium;"> True</span>
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<div><br /></div><span style="font-size: medium;"><b> Bài 20a </b>
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<span style="font-size: medium;"> Bài 20</span>
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</span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></span></div>

VII/ Read the passage and then decide whether the sentences are True or False

TEXT A -WHAT IS A TSUNAMI A tsunami is a string of large ocean waves. Some people call it a “wave train" or a "tidal wave....

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VII/ Read the passage and then decide whether the sentences are True or False

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